An industrial vat contains 650 grams of solid lead (ll) chloride formed from areaction of 870 grams of lead (ll) nitrate with excess hydrochloride acid. this is the equation of the reaction

Answer is: The percent yield of lead chloride is 88%.

Balanced chemical reaction: 2HCl + Pb(NO₃)₂ → 2HNO₃ + PbCl₂.

m(PbCl₂) = 650 g; mass of lead (II) chloride.

m(Pb(NO₃)₂) = 870 g; mass of lead (II) nitrate.

n(Pb(NO₃)₂) = 870 g ÷ 331.21 g/mol.

n(Pb(NO₃)₂) = 2.63 mol; amount of lead (II) nitrate.

From balanced chemical reaction: n(Pb(NO₃)₂) : n(PbCl₂) = 1 : 1.

n(PbCl₂) = 2.63 mol; amount of lead (II) chloride.

m(PbCl₂) = 2.63 mol · 278.1 g/mol.

m(PbCl₂) = 731.4 g.

yield = 650 g ÷ 731.4 g · 100%.

yield = 88.88 %.

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.

po-215 i got it right on the quiz