How to calculate how many moles of o are in 22.4 mol of fe(no3)3

Hey there:

1 mole of Fe(NO3)3 9 moles of O

22.4 moles Fe(NO3)3  ??

22.1 * 9 / 1 =>

198.9 moles of O

Hope that helps!

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons