Determine the empirical formula of a hydrate fexfy. zh2o. it contains 0.676 g of iron combined with 0.460 g of fluorine and 0.870 g of water (h2o).

Hey there!:

Number of moles of iron:

Molar mass iron:  55.85 g/mol

0.676 / 55.85 => 0.012 moles of iron

Number of moles of fluorine:

Molar mass fluorine : 19 g/mol

0.460 / 19 => 0.024 moles of fluorine

Number of moles of water:

Molar mass water : 18.02 g/mol

0.870 / 18.02 => 0.048 moles of water

Simplest  mol ratio is :

iron ( Fe ) = 0.012 / 0.012 => 1.0 mol

Florine ( F ) = 0.024 / 0.012 => 2.0 moles

Water ( H2O ) = 0.048 / 0.012 =>  4 moles

Therefore:

Empirical formula is:

FeF2.4H2O

Hope that helps!

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