Achemist is working on a reaction represented by this chemical equation: fecl2 + 2koh → fe(oh)2 + 2kcl. if the chemist uses 4.15 moles of iron(ii) chloride and 3.62 moles of potassium hydroxide, how many moles of iron(ii) hydroxide will the reaction produce? a. 1.81 mol b. 3.62 mol c. 4.15 mol d. 7.24 mol

Answer is: A. 1.81 mol.

Balanced chemical reaction: FeCl₂ + 2KOH → Fe(OH)₂ + 2KCl.

n(FeCl₂) = 4.15 mol; amount of iron(II) chloride.

n(KOH) = 3.62 mol; amount of potassium hydroxide, limiting reactant.

From chemical reaction: n(KOH) : n(Fe(OH)₂) = 2 : 1.

n(Fe(OH)₂) = n(KOH) ÷ 2.

n(Fe(OH)₂) = 3.62 mol ÷ 2.

n(Fe(OH)₂) = 1.81 mol; amount of iron(II) hydroxide.

It's A. 1.81 mol. This answer is on Plato.

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