What is the mass of 4.32 mol gai3? 455 g 1,230 g 1,720 g 1,950 g

Answer is: the mass of gallium iodide (GaI₃) is 1,950g.

n(GaI₃) = 4.32 mol; amount of the galium iodide.

M(GaI₃) = Ar(Ga) + 3 · Ar(I) · g/mol.

M(GaI₃) = 69.72 + 3 · 126.9 · g/mol.

M(GaI₃) = 69.72 + 380.7 · g/mol.

M(GaI₃) = 450.42 g/mol; molar mass of gallium iodide.

m(GaI₃) = n(GaI₃) · M(GaI₃).

m(GaI₃) = 4.32 mol · 450.42 g/mol.

m(GaI₃) = 1946 g; mass of gallium iodide.

What is the mass of 4.32 mol GaI3?

455 g

1,230 g

1,720 g

1,950 g CORRECT ANSWER

I took the test and D) was correct

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.