Consider the reaction 2al + 6hbr → 2albr3 + 3h2. if 8 moles of al react with 8 moles of hbr, what is the limiting reactant? al albr3 h3 hbr

- HBr is limiting reactant.

Solution:- The given balanced equation is:

From this equation, There is 2:6 mol or 1:3 mol ratio between Al and HBr. Since we have 8 moles of each, HBr is the limiting reactant as we need 3 moles of HBr for each mol of Al.

The calculations could be shown as:

= 24 mol HBr

From calculations, 24 moles of HBr are required to react completely with 8 moles of Al but only 8 moles of it are available. It clearly indicates, HBr is limiting reactant.