The atomic mass of 13c is 13.003355. multiply the atomic mass of 13c by its abundance. report the number to 8 significant digits.

Answer is: number is 0.14303691.

Carbon-13 (¹³C) is a stable isotope of carbon with mass number 13, it has six protons and seven neutrons.

Isotopes are chemical elements with same atomic number, but different mass number (different number of neutrons).

ω(¹³C) = 1.10% ÷ 100%.

ω(¹³C) = 0.0110; abundance of carbon-13 in nature.

m(¹³C) = 13.003355; the atomic mass of carbon-13.

ω(¹³C) · m(¹³C) = 0.0110 · 13.003355.

ω(¹³C) · m(¹³C) = 0.14303691.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied