Na2o2 + co2 → na2co3 + o2 what volume of o2 gas is produced from 2.80 liters of co2 at stp?

The volume of O2 gas  that is produced from  2.80 L of CO2 at STP is  1.40 L

write a balanced chemical equation

2Na2O2 + 2CO2 → 2Na2CO3 +O2

by use of mole ratio between CO2:O2 which is 2:1 the number of liters of O2 produced is therefore= 2.8 x 1/2 =1.40 Liters

The volume of produced will be 1.4 liters.

Explanation:

AT STP, the conditions are:

1 mole of a gas occupies 22.4 liters of volume.

The balanced chemical equation for the reaction follows:

By Stoichiometry of the reaction:

2 moles of carbon dioxide produces 1 mole of oxygen gas, which means that

44.8 liters of carbon dioxide gas produces 22.4 liters of oxygen gas.

So, 2.8 liters of carbon dioxide gas will produce = of oxygen gas.

Hence, the volume of produced will be 1.4 liters.

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gas

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smoke is the matter of a gas