Chemistry, 08.07.2019 04:00 savannahsims5847

How many liters of oxygen (at stp) are required to form 10.5 g of h2o?

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In a liter of gas AT STP, there's 22.414 moles. That is something to remember.

You want to make 10.5g of water, but we don't know how much that is until we know how many moles that is of water.

The molecular weight of water is about 18.02g/mol

so for every mole, or 6.022*10^23 molecules of water, that's 18.02 grams.

Ok, but you want 10.5 grams of water, so it's a proportion.

18.02g/1mol = 10.5g/?mol

solve for unknown to get moles and you get

(1/18.02)*10.5 = 0.5826859046... don't round yet to 3 significant figures.

That's how many moles of water you want.

Now for every mole of water, there's 2 moles of hydrogen and one mole of oxygen. But the ratio of oxygen to water is 1:1.

In other words, you need x amount of oxygen to make x amount of water, the same.

So knowing that you need 0.5826859046 moles of oxygen you need and that there's 22.414 moles of a gas in 1 L at STP, you can find how many liters this is.

22.414mol / 1L = 0.5826859046mol / XL

this number is big because it should still be in your calculator, we don't round until the end.

= 0.0259965...
NOW round to 3 significant figures originally from 10.5g in the problem and get

0.0260 L of oxygen needed

Answer from: Quest

i don,t know so just answer mine

Answer from: Quest

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.

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