How many grams of kbro2 are there in 0.168 moles

Hey There!

Molar mass KBrO2 = 151.0011 g/mol

1 mole KBr 151.0011 g

So in 0.168 moles :

mass = number of moles * molar mass

mass = 0.168 * 151.0011

mass = 25.36 g of KBrO2

i believe it is a.) released into

explanation:

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.