How many moles of pbr3 contain 3.68 ã 1025 bromine atoms?

Given data:

# atoms of Br in PBr3 = 3.68 * 10^25

Explanation:

In PBr3,

1 mole of PBr3 contains 3 moles of Br

Now,

1 mole of Br contains Avogadro number i.e. 6.023 * 10^23 atoms of Br

Therefore, the # moles of Br corresponding to 3.68*10^25 atoms would be:

= 3.68 * 10^25 atoms * 1 mole Br/6.023*10^23 atoms = 61.099 moles of Br

Since,

3 moles of Br is present in 1 mole of PBr3

then, 61.099 moles of Br would correspond to:

61.099 moles Br * 1 mole PBr3/3 moles Br = 20.366 moles of PBr3

Ans: 20.4 moles of PBr3

beta decay is the answer

just did the assignment and the answer was #1 +2 n