Students working in lab accidentally spilled 17 l of 3.0 m h2so4 solution. they find a large container of acid neutralizer that contains baking soda, nahco3. how many grams of baking soda will be needed to neutralize the sulfuric acid spill? do not include a unit in your answer or it will be counted wrong. use correct significant figures

The mass of baking soda required is 4284 g.

The reaction equations given as;

H2SO4(aq) + NaHCO3(aq) >  H2O(l) + CO2(g) + NaHSO4(aq)

The number of moles of H2SO4 that was spilled is obtained from;

n = 17 L × 3M = 51 moles

We can see from the reaction equation that the reaction is a 1:1 reaction, this implies that 51 moles of NaHCO3.

Hence, mass of baking soda required = 51 moles ×84 g/mol = 4284 g

Learn more about neutralization: link

the formula would be mgso4

mgso[subscript]4

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