For the reaction shown, identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent. kno3 → kno2 + o2

The oxidized element is, oxygen.

The reduced element is, nitrogen.

The oxidizing agent is, nitrogen.

The reducing agent is, oxygen.

Explanation:

Answer : The oxidizing element is N and reducing element is O. 

is act as an oxidizing agent as well as reducing agent.

Explanation :

An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.

Reducing agent is the agent which has ability to reduce other or lower in oxidation number.

The given reaction is :

 act as an oxidizing agent.

The oxidation number of N in is calculated as:

(+1)+(x)+3(-2) = 0

x = +5

And the oxidation number of N in  is calculated as:

(+1)+(x)+2(-2) = 0

x = +3

From the oxidation number method, we conclude that the oxidation number  reduced this means itself get reduced to and it can act as an oxidizing agent.

 act as a reducing agent.

The oxidation number of O in is calculated as:

(+1)+(+5)+3(x) = 0

x = -2

The oxidation number of O in is Zero (o).

Now, we conclude that the oxidation number increases this means itself get oxidized to and it can act as reducing agent.

5.6⋅10−^19  j

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