What is the radiation particle used in the bombardment of boron-10? boron-10 plus a radioactive particle yields nitrogen-13 plus a neutron?

In the given nuclear reaction, one of the reactant is Boron-10, and the products are Nitrogen-13 and neutron. So, the sum of mass numbers of Nitrogen - 13 and neutron is 13 + 1 =14 and the sum of atomic numbers is 7 + 0 = 7 on the product side. On the reactant side the other reactant will have a mass number of 14 - 10 = 4 and an atomic number of 7-5 = 2. So, the other reactant will be alpha particle.

This nuclear reaction representing the bombarding of Boron-10 with the radioactive alpha particle to yield Nitrogen-13 and a neutron is:

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

catya your not at all which answer i've seen you do this on another question!