Ccl, 189.86 g/mol. express your answer as a chemical formula.

Answer is: a chemical formula of the compound is C₄Cl₄.

CCl is empirical formula of the compound. Empirical formula gives the proportions of the elements present in a compound, so we know that proportion od carbon and chlorine is 1 : 1 (n(C) : n(Cl) = 1 : 1).

M(CCl) = Ar(C) + Ar(Cl) · g/mol.

M(CCl) = 12.0107 + 35.453 · g/mol.

M(CCl) = 47.4637 g/mol; molar mass of empirical formula.

M(compound) = 189.86 g/mol; molar mass of the compound.

M(compound) / M(CCl) = 189.86 g/mol / 47.4637 g/mol.

M(compound) / M(CCl) = 4; chemical formula of the compound have four carbon and four chlorine atoms.

practical process described pest part of scientific investigation.

because practical knowledge is powerful then therotical knowledge.