In the reaction, a → products, a plot of ln[a] vs. time is linear and the slope is equal to -0.860 s-1. how long will it take one-half of the initial amount of a to react?

The study of chemicals and bonds is called chemistry. There are different types of elements and these are metals and nonmetals.

The correct answer is -0.806sec.

The plot for ln[a] verses t is linear for a first-order reaction. The integrated rate law equation is as follows:

Here,

The equation will be:-

Compared with the equation for linear graph, y=mx+c

Thus, slope =-k

The value of k will be 0.860

Now, if the final concentration becomes half of its initial value .

Place all the values and rearrange them.

Hence, the correct answer is 0.860.

For more information about the half-life, refer to the link:-

link

The reaction is given as follows:

The plot of ln[a] verses t is linear with slope .

The plot for ln[a] verses t is linear for first order reaction. The integrated rate law equation is as follows:

Here, k is rate constant, t is time of the reaction, is concentration of reactant at time t and is initial concentration of reactant.

Taking ln both sides,

...... (1)

Comparing with equation for linear graph, y=mx+c

Thus, slope =-k

Or,

Now, if final concentration become half of its initial value, and t becomes

Putting the values in equation (1)

On rearranging,

Therefore, it takes 0.806 sec to react half of the reactant a.

i know insulin is primary but i dont know the others im sorry

explanation:

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

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(jacemorris04)