If a sample of 0.150 g of kcn is treated with an excess of hcl, calculate the amount of hcn formed in grams.

write the equation for reaction

that is;  KCn + HCl → KCl + HCn

 step 1:find the moles of KCn reacted

moles of KCn = mass of KCn/molar mass of KCn( 65.12 g/mol)

= 0.150 g/ 65.12 g/mol =2.303 x10^-3  moles

step 2: use the mole ratio between KCn :HCn  which is 1:1  to determine the moles of HCn   which is also  2.303 x 10^-3 moles

step 3: find the mass  of HCn =moles of HCn  x molar mass of HCn

= 2.303 x10^-3 x 27. 02 =0.06223 grams

c. orbital shape i hope this is correct