During the bromination of methane, the free radical ch3• is generated. a possible terminating step of this reaction is the formation of c2h6 by the combination of two free radicals. what could be produced in a terminating step during the bromination of propane ?

The answer is (CH₃)₂CH-CH(CH₃)₂.

That is the free radical generated in bromination of propane is (CH₃)₂CH° and CH₃CH₂CH₂° , but due to more stability of secondary free radical , (CH₃)₂CH° is more stable than that of CH₃CH₂CH₂°, so reaction proceeds via (CH₃)₂CH° radical. and than at termination the the product formed will be (CH₃)₂CH-CH(CH₃)₂.

i think slash and

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.