Combustion analysis of a hydrocarbon produced 33.01 g co2 and 27.02 g h2o. calculate the empirical formula of the hydrocarbon.

The empirical formula of hydrocarbon is CH4

explanation

Hydrocarbon contain both hydrogen(H) and carbon(C)

calculate the mass of  C  and H

mass of C  from CO2= 12/44x33.01=9.003 g

mass of H from H2O =2/18 x27.02 =3.002 g

find the number  of moles of C and H

mole=mass/molar mass

moles  of C=  9.003g/12g/mol=0.7503 moles

moles of H=  3.002g /1g/mol = 3.002 moles

find the mole ratio of each element by dividing each  mole with smallest number of mole  ( 0.7503 moles)

that is C=0.7503/0.7503=1

          H=3.002/0.7503=4

therefore the empirical formula= CH4

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first one is the correct answer