One mole (mol) of glucose (molecular mass = 180 daltons) is a 180 × 1023 molecules of glucose. b 1 kg of glucose dissolved in 1 l of solution. c the largest amount of glucose that can be dissolved in 1 l of solution. d 180 kilograms of glucose. e both 180 grams of glucose and 6.02 × 1023 molecules of glucose.

Answer;

E. both 180 grams of glucose and 6.02 × 1023 molecules of glucose

Explanation;

-One mole of any substance contains 6.02 ×10^23 particles, which is known as the Avagadro's contant.

-Avogadro's number, number of units in one mole of any substance (defined as its molecular weight in grams), equal to 6.022140857 × 1023. The units may be electrons, atoms, ions, or molecules, depending on the nature of the substance and the character of the reaction.

-Therefore; 1 mole of glucose contains 6.02 ×10^23 molecules which is equivalent to a mass of 180 g.

it is b that is the answer.