A0.3146-g sample of a mixture of nacl(s) and kbr(s) was dissolved in water. the resulting solution required 55.00 ml of 0.08765 m agno3(aq) to precipitate the cl–(aq) and br–(aq) as agcl(s) and agbr(s). calculate the mass percentage of nacl(s) in the mixture.

The balanced chemical equation representing the reaction of NaCl with AgNO3 is,

The balanced chemical equation representing the reaction of KBr with AgNO3 is,

Moles of =

0.00482075 mol completely removes Chlorides and bromides in the sample.

Mole ratio of

Mole ratio of

So, the total moles of chloride and bromide in the sample = 0.00482075 mol

Let mass of NaCl be x g

Mass of KBr be y g

Total mass of sample = 0.3146 g

=> x + y = 0.3146 g

x = 0.3146 -y

Total number of moles of NaCl + KBr = 0.00482075 mol

Therefore mass of KBr = 0.0646 g

Mass of NaCl = 0.3146 - 0.0646 g = 0.250 g

Mass % of NaCl in the sample =

the answer is 0.8m.

by: nicholas

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