If the enthalpy change for the combustion 2.00 g of propane, c3h8, was determined to be −102.5 kj by calorimetry, what is the calculated enthalpy change for the combustion of one mole of propane under the same conditions?

- -2260 kj.

Solution:- It could easily be solved using dimensional analysis. From given information, the enthalpy change for the combustion of 2.00 grams of propane is -102.5 kj. It asks to calculate the enthalpy change in same conditions for the combustion of 1 mole of propane.

We convert 1 mole of propane to grams using molar mass(44.1 gram per mol) and then calculate the heat using the given information as:

= -2260 kj

Hence, the enthalpy change for the combustion of 1 mol of propane is -2260 kj.