One isotope of aluminum is 27/13al. how many electrons would a neutral atom of this isotope contain?

A neutral atom of _13^27Al contains 13 electrons.

The atomic number is 13, so the atom has 13 protons (+).

If the atom is neutral, it must contain 13 electrons (-).

c. the scientist provides unbiased information to the government.

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.