What is the limiting reactant if 70.0 g of c7h6o3 and 80.0 g of c4h6o3 react?

Given:

70g C7H6O3

80g C4H6O3

Required:

Limiting reactant

Solution:

The balanced chemical reaction is C7H6O3 + C4H6O3 + 23/4O2 -> 11CO2 + 6H2O

Molar mass of C7H6O3 = 138 g/mol

Molar mass of C4H6O3 = 102 g/mol

70g C7H6O3 (1 mol C7H6O3/138g C7H6O3)(1 mol C4H6O3/ 1mol C7H6O3)(102g C4H6O3/1mol C4H6O3) = 51.74g C4H6O3

80g C4H6O3 - 51.74g C4H6O3 = 28.26g C4H6O3

There are 28.26g C4H6O3 left after reacting it with C7H6O3, therefore the limiting reactant is C7H6O3.

the answer is d : ) have a good da

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