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Chemistry, 12.07.2019 02:30 jdkrisdaimcc11
Aluminum hydroxide reacts with sulfuric acid as follows: 2 al(oh)3(s) + 3 h2so4(aq) → al2(so4)3(aq) + 6 h2o(l). which reagent is the limiting reactant when 0.410 mol al(oh)3 and 0.410 mol h2so4 are allowed to react? h2so4 al2(so4)3 h2o al(oh)3 correct: your answer is correct. how many moles of al2(so4)3 can form under these conditions? 0.137 correct: your answer is correct. mol how many moles of the excess reactant remain after the completion of the reaction?
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Aluminum hydroxide reacts with sulfuric acid as follows: 2 al(oh)3(s) + 3 h2so4(aq) → al2(so4)3(aq)...
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