30 cubic meters of argon gas are kept under constant pressure. the gas is heated from 10.0 degrees celsius to 293 degrees celsius. what is the new volume of the gas?

            V₂  =  60 cm³

Explanation:

                    According to Charle's Law, "Volume of given amount of gas is directly proportional to applied temperature at constant pressure". Mathematically,

                                                 V₁ / T₁  =  V₂ / T₂     (1)

Data Given:

                   V₁  =  30 cm³

                   T₁  =  10 °C  =  10 + 273  =  283 K

                   V₂  =  ?

                   T₂  =  293 °C  =  293 + 273  =  566 K

Solution:

Solving equation 1 for V₂,

                   V₂  =  V₁ × T₂ ÷ T₁

Putting values,

                   V₂  =  (30 cm³ × 566 K) ÷ 283 K

                   V₂  =  60 cm³

the formula for the conversion of temperature from degree celsius to kelvin is:

the sample of water at is converted to kelvin temperature by using the above formula as:

on comparing the two samples of water at or we can say that at and at respectively. the difference between the temperatures of two samples of water is:

hence, one can say that the sample of water at is greater than the sample of water at by .