Ageochemist has determined by measurements that there are 33.7 moles of tin in a sample of cassiterite. how many moles of oxygen are in the sample?

             67.4 mol of O atoms

Explanation:

Cassitrerite is a Tin Mineral having a chemical formula SnO₂. As seen in chemical formula there are two moles of Oxygen atoms for each Tin atom. So we can conclude that,

For,

               1 mole of Sn in SnO₂ there are  =  2 moles of O atoms

So for,

               33.7 moles of Sn there will be  =  X moles of O atoms

Solving for X,

                     X  =  (33.7 mol of Sn × 2 mol of O) ÷ 1 mol of Sn

                     X  =  67.4 mol of O atoms

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

explanation:

0.07 g/cm³

1.37 g/cm³