Achemist adds 220.0ml of a 0.194 m potassium permanganate kmno4 solution to a reaction flask. calculate the mass in grams of potassium permanganate the chemist has added to the flask

The formula of determining the molarity is:

molarity =   -(1)

Volume of solution =  (given)

Since, 1 mL = 0.001 L

Therefore, volume of the solution = 0.22 L

Molarity = 0.194 M  (given)

Substituting the values in formula (1)

Now, number of moles =  -(2)

Molar mass of =

Substituting the value of number of moles and molar mass of in equation   -(2)

Hence, the mass in grams of potassium permanganate the chemist has added to the flask is .

c-14 is carbon-14, or radiocarbon.   it is a radioactive isotope of carbon with an atomic nucleus containing 6 protons and 8 neutrons.

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole