The daily production of carbon dioxide from an 780.0 mw coal-fired power plant is estimated to be 3.3480 x 104 tons (not metric).a proposal has been made to capture and sequester the co2 at approximately 300 k and 140 atm. at these conditions, the specific volume of co2 is estimated to be 0.0120 m3/kg. what volume of co2 would be collected in a 4.00 year period?

The production of is . Converting mass into kg,

1 ton=907.185 kg, thus,

Thus, production of will be .

The specific volume of is .

Volume of produced per day can be calculated as:

Putting the values,

Thus, volume of produced per year will be:

Thus, in 4 year volume of produced will be:

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.