When 8.0 mol mg react with 13.5 mol hci, what is the limiting reactant and how many moles of h2 can be formed?

The answer is :

HCl is the limiting reactant and 6.75 mol can be formed.

The explanation:

1- we need to get the balanced reaction equation:

Mg + 2HCl > MgCl2 + H2

Here, you can see from the balanced chemical equation, that 1 mol Mg reacts with 2 mol HCl.

2-by using stoichiometry for each reactant:

So, 8 mol Mg should react with 2* 8 mol HCl

So, 8 mol Mg should react with 16 mol HCl

But the given amount of HCl is 13.5 mol, which is less than the required (16 mol) to react completely with Mg.

-now Amount of HCl is less So, HCl is the LIMITING REAGENT.

-when limiting reagent (or limiting reactant, LR) in a chemical reaction is the substance that is totally consumed when the chemical reaction is complete. The amount of product formed is limited by this reagent.

Also, you can see that 2 mol HCl corresponds to the formation of 1 mol H2.

SO, 1 mol HCl corresponds to the formation of 1/2 mol H2.

1 mol HCl → 1/2 mol H2

13.5 mol HCl→

13.5 mol HCl corresponds to the formation of (1/2)*13.5 mol H2 = 6.75 mol H2.

So, HCl is the limiting reactant, and 6.75 mol H2 can be formed.

2b2t

explanation:

2b2t