How many milliliters of pure liquid methanol (ch3oh, mw = 32.04 g/mol) are needed to prepare 500.0 ml of an aqueous solution of 12.0 g/l methanol? the density of pure liquid methanol is 0.791 g/ml?

- 7.59 mL.

Solution:- We want to make 500.0 mL of an aqueous solution of methanol whose density is . This has to be made from a given pure liquid methanol with density . It asks to calculate the volume of pure liquid methanol.

We know that, mass = volume*density

Let's calculate the mass of aqueous solution from it's given volume and density. need to convert volume unit from mL to L as the density is given in grams per liter:

mass of aqueous methanol solution =

= 6 g

From above calculations, we need to use 6 g of pure liquid methanol. It's density is known, so we could calculate it's volume as:

Let's plug in the values in it:

= 7.59 mL

Hence, we need to take 7.59 mL of pure liquid methanol.

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.

thats a little if u want the answer just look it up on google thats what i do haha : )