Ascientist makes an acid solution by adding drops of acid to 1.2 l of water. the final volume of the acid solution is 1.202 l. assuming the volume of each drop is 0.05 ml, how many drops were added to the water? about what percent of the acid solution is acid?

- 40 drops and the percentage of acid in acid solution is 0.166%.

Solution:- Acid is added drops wise to 1.2 L of water to make acid solution. The final volume of the acid solution is 1.202 L. From here we could calculate the volume of the acid added to water by subtracting water volume from final acid solution volume as:

volume of acid added = 1.202 L - 1.2 L = 0.002 L

It's given that the volume of each drop is 0.05 mL. let's convert the volume of acid added from L to mL.

= 2mL

Now let's calculate the number of drops of acid added to water as:

= 40 drops

0.002 L of acid are present in 1.202 L of solution. It asks to calculate about what percent of acid solution is acid means how many L of acid are present in 100 L of acid solution. It's done as:

percentage of acid in acid solution =

= 0.166%

So, 40 drops of acid are required and there is 0.166% of acid in acid solution.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

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