What is the empirical formula of an unknown compound that contains 60.3% of magnesium and 39.7% of oxygen?

- Empirical formula is MgO.

Solution:- From given information,

Mg = 60.3%

O = 39.7%

Percentages could be considered as their grams and to convert them to moles we divide by their atomic masses.

moles of Mg =  = 2.48 mole

moles of O =  = 2.48 moles

We have equal moles of Mg and O, it means the mole ratio is 1:1 and so the empirical formula is MgO.

metals are good conductor of electricity. it has free electrons on their surface. according to electron pool theory, each atom present in a metal crystal losses all of its valence electron and as a result a pool of free is form. these pool of electrons are free to move and   conduct electricity easily   while making metal as good conductor.

the correct answer is a. the ability of electrons to flow throughout the metal.

if it's not useful, feel free to report for mistake in answer.

the answer is c.the valence of the atoms combine .