How many grams of sodium bicarbonate are needed to make 23.75ml of a 4.861 m solution

96.99 g NaHCO_3

Step 1. Calculate the moles of NaHCO_3

Moles of NaHCO_3 = 0.2375 L solution × (4.861 mol NaHCO_3/1 L solution)

= 1.1545 mol NaHCO_3

Step 2. Calculate the mass of NaHCO_3

Mass of NaHCO_3

= 1.1545 mol NaHCO_3 × (84.01 g NaHCO_3/1 mol NaHCO_3)

= 96.99 g NaHCO_3

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explanation:

a pan containing water is placed in a positio n where it is exposed to a 10 mile per hour wind. the pan contains a uniform depth of 1.27 cm of water, is quite wide, and has a length of 2.44 m in the wind direction. the water in the pan is at a constant temperature of 15.5 °c.