What mass of fe can be produced by the reaction of 75.0 g co with excess fe2o3 according to the equation: fe2o3(s) + co(g) → fe(s) + co2(g)?

99.7 g Fe

Step-by-step explanation:

a)Write the balanced chemical equation

Fe2O3 + 3CO → 2Fe + 3CO2

b)Convert grams CO to moles CO

Moles CO = 75.0 g CO x (1 mol CO/28.01 g CO) = 2.678 mol CO

c)Use the molar ratio of Fe:CO to convert moles of CO to moles of Fe

2.678 mol CO x (2 mol Fe/3 mol CO) = 1.785 mol Fe

d)Convert moles of Fe to grams of Fe

1.785 mol Fe x (55.84 g Fe/1 mol Fe) = 99.7 g Fe

law of conservation of matter

c8h10 is your answerr