Ateacher calculates the molar mass of sodium hydroxide as 37 g/mol. the true molar mass of sodium hydroxide is 40 g/mol. find the teachers percent error

Solution : Teachers percent error is 7.5%

Percent error can be calculated by using the percent error formula.

Accepted value is the true value.

Measured values is the calculated value.

In our question the True value (Accepted value) is given as 40 g/mol

Measured value (calculated value) is given as 37 g/mol

We will plug in the accepted value and measured value in the percent error formula and calculate the value of percent error.

Percent error = 7.5 %

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: