If it takes 25.0 ml of m naoh solution to standardize 10.0 ml of hcl, what is the exact concentration of hcl?

-

2.5 M

Explanation: -

Volume of NaOH = 25.0 mL

= 25.0/1000 = 0.025 L

Strength of NaOH = 1 M

Number of moles of NaOH = Volume of NaoH x strength of NaOH

= 0.025 L x 1 M

= 0.025 mol

Volume of HCl = 10.0 mL = 10.0/1000 =0.01 L

The balanced chemical equation for the reaction of HCl and NaOH is

HCl + NaOH→ NaCl + H₂O

At the equivalence point,

Number of moles of HCl =Number of moles of NaOH

Strength of HCl x Volume of HCl = 0.025 mol

Strength of HCl x 0.01 L = 0.025 mol

Strength of HCl = 0.025 / 0.01 = 2.5 M

Thus If it takes 25.0 ml of M NaOH solution to standardize 10.0 ml of HCl, 2.5 M is the exact concentration of HCl

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