Using the formula 5kmno2+2kmno4+3h2so4=5kno3+2mnso4+k 2so4+3h20. how many moles and grams of kmno4 are needed tk provide 145 grams of kno3?

0.576 mol of KMnO₄

91.0 g of KMnO₄

Explanation: -

Molar mass of KNO₃ = 39 x 1 + 14 x 1 + 16 x 3

= 101 g/ mol

Mass of KNO₃ =145 grams

Number of moles of KNO₃ =145 g / (101 g/ mol)

= 1.44 mol

The chemical equation for the reaction is

5 KNO₂ + 2KMnO₄ + 3 H₂SO₄ →5 KNO₃ + K₂SO₄ + MnSO₄ + 3 H₂O

From the balanced chemical equation we see

5 mol of KNO₃ is produced from 2 mol of KMnO₄

1.44 mol of KNO₃ is produced from mol of KMnO₄

= 0.576 mol of KMnO₄

Molar mass of KMnO₄ = 39 x 1 + 55 x 1 + 16 x 4

= 158 g /mol

Mass of KMnO₄ = 158 g /mol x 0.576 mol of KMnO₄

= 91.0 g

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.