What is the change in energy of an atom if the wavelength of the photon absorbed by the atom is equal to 4.64 x 10-7 meters? (planck’s constant is 6.626 x 10-34 joule seconds; the speed of light is 2.998 x 108 m/s)?

Hello!

We have the following data:

v (speed of light) =

λ (wavelength) =

First, let's find the frequency of the wave, let's see:

Now, find the Energy of the Photon by Planck's Equation, given:

E (photon energy) =? (in Joule)

h (Planck's constant) =

f (radiation frequency) =

Therefore, we have:

I Hope this helps, greetings ... DexteR! =)

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.