How would you use ir and 1h-nmr spectroscopy to distinguish between these two isomeric compounds? isomer a.4-methoxypentanoyl chloride isomer b.6-chlorohexanoic acid g?

A carboxyl group is present in 6-chlorohexanoic acid having IR peak between 1690 -1760 Cm-1 whereas in 4-methoxypentanoyl chloride , a carbonyl group is present as oyl chloride as having peak between 1715 -1745 Cm-1.

Now, in 4-methoxypentanoyl chloride , the peaks are (1 H, m) , (2 H, t ), (2 H , q ) whereas in 6-chlorohexanoic acid , the peaks are (2 H, m), (2 H, m ), (2 H , t )

explanation:

i think option no d is the correct answer

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !