If the compound methane (ch4) has no lone pairs, it would take which shape? a. linear compound b. tetrahedral compound c. trigonal planar compound d. trigonal bipyramid

Answer : The correct option is, (B) Tetrahedral compound

Explanation :  

Formula used:

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

First we have to determine the hybridization of the molecule.

The number of electrons are 4 and there is no lone pairs present on the central carbon atom that means the hybridization will be and the electronic geometry of the molecule will be tetrahedral.

Hence, the shape of the given compound is, tetrahedral.

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.