How many grams are in 2.30 x 10^24 atoms in silver

411.984 grams

The atomic mass of Silver is 107.8682 by the periodic chart I have here. That means that 1 mole of Silver masses

107.8682 grams if the Silver is pure.

I mole of any element like silver is also 6.022 X 10^23 atoms of silver.

10^24 atoms is therefore more than a mole. You specified

2.3 x 10^24 atoms, so the number of moles will be

(2.3 X 10^24)divided by 6.022 X 10^23 = 3.819 moles

this number X 107.8682 grams/mole gives us 411.984 grams

413 g of Ag  are in 2.30 x 10^24 atoms in silver.

From Avogadro's law, we know that the number of elementary entities in one mole of a substance is given by the Avogadro's number, 6.02 × 10^23 atoms.

In this case, we are told that there are 2.30 x 10^24 atoms in silver. We can find the mass of this number of silver atoms using the Avogadro's number as follows;

1 mole of Ag atoms contain 6.02 × 10^23 atoms

x moles of silver atoms contain 2.30 x 10^24 atoms

x = 1 mole × 2.30 x 10^24 atoms/ 6.02 × 10^23 atoms

x = 3.82 moles of Ag

Mass of  3.82 moles of Ag =  3.82 moles of Ag  x 108 g/mol

= 413 g of Ag

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2b2t

explanation:

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