What is the poh of a 0.0010 m solution of calcium hydroxide (ca(oh)2)

The pOH is: " 2.40 " .

The pOH value of a 0.0010 M solution of calcium hydroxide;

Ca(OH)₂ ; is:

" 2.40 " .

Explanation:

Calculate the pOH of a 0.0010 M solution of Ca(OH)₂ .

Note that:

"M" represents the concentration in "Molarity" ;

(that is; "moles of solute per Liter of solution" ; or, "mol / L " } ;

and that for our purposes, anything notes in "brackets" refers to "concentration"; in "M" {"Molarity" ; as explained above.}.

Note that "calcium hydroxide", that is; " Ca(OH)₂ " ;

→ dissociates into the following ions, as follows:

→ Ca(OH)₂ → Ca²⁺ + 2 OH⁻ ;

Therefore, the [OH⁻] equals: {2 * 0.0010} M = 0.0040 M .

For every Ca(OH)₂ you produce 2 OH⁻ .

Note: pOH = - log [OH⁻] ;

pOH = - log ( 0.0040) = 2.3979400086720375 ;

→ round to: " 2.40 " .

The pOH is: " 2.40 " .

The pOH value of a 0.0010 M solution of calcium hydroxide; Ca(OH)₂ ; is:

" 2.40 " .

it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.

it should have an internal chamber and two thermometers sticking out of the top. the internal chamber will also be closed off from the outside.