Chemistry, 15.07.2019 06:30 Amyra2003

Which of the following statements is true? the atmosphere is an example of a solution. in a glass of sugar water, sugar is the solvent. the individual substances in a mixture lose their original chemical properties. all of the above.

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Only the third option is true: The individual substances in a mixture lose their original chemical properties. The atmosphere is most definitely not a solution and sugar is not a solvent.

Answer from: LindaCat78

The individual substances in a mixture lose their original chemical properties

Explanation:

A solution is formed by solutes and solvent. The solvent is the compound that is capable of dissolving the other compounds. A mixture occurs when two or more compounds are together without react.

So, the atmosphere is a mixture of gases, not a solution.

In a glass of sugar water, the sugar is the solute and the water is the solvent because the sugar is the compound which is dissolved.

In a mixture, the individual substances contribute to the chemical properties of the mixture, but they now will be different. For example, the air is less reactive than oxygen pure, because the air is a mixture of gases. So, the individual substances lose their original chemical properties.

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

Ithink is a because if say increased in electronegativity

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