What is the ph of 0.51 m ca(ch3coo)2 solution?

Answer : The pH of calcium acetate solution will be 9.38.

Explanation : When calcium acetate dissocates completely in solution to form Calcium(+2) ions and two acetate ions, this gives the acetate ion concentration as (2 X 0.51 M) = 1.02 M

Acetate ion then hydrolyzes as follows;

:

Now, Kb will be = /

= Kw / Ka

= 1 x / 1.8 x = 5.6 ×

= 2.4 ×

Now, we know , pOH = -log = 4.62

So, the pH = 14 - pOH = 14 - 4.62 = 9.38