Chemistry, 15.07.2019 14:30 Savageman4654
Sodium hydroxide reacts with carbondioxide as follows: 2 naoh(s) + co2 (g) → na2co3 (s) + h2o(l) which reagent is the limiting reactant when 1.85 mol of sodium hydroxide and 1.00 mol carbondioxide are allowed to react? how many moles of sodium carbonate can be produced? how many moles of the excess reactant remain after the completion of the reaction?
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Answer asap need it by wednesday morning carry out the following calculations on ph and ka of from data. i. calculate the ph of 0.02m hcl ii. calculate the ph of 0.036m naoh iii. calculate the ph of 0.36m ca(oh)2 iv. calculate the ph of 0.16m ch3cooh which has ka = 1.74 x 10-5 mol dm-3 v. calculate ka for weak acid ha which has a ph of 3.65 at 0.30m concentration vi. calculate the ka of a solution made by mixing 15.0 cm3 0.2m ha and 60.0 cm3 0.31m a-. [ph= 3.80] vii. calculate the ph of a solution made by mixing 15.0 cm3 0.1m naoh and 35.0 cm3 0.2m hcooh. [ka = 1.82 x 10-4 m]
Answers: 1
Sodium hydroxide reacts with carbondioxide as follows: 2 naoh(s) + co2 (g) → na2co3 (s) + h2o(l) wh...
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