Answers: 1
![-pOH= log [ OH^{-}]](/tpl/images/1058/8779/99511.png)
![[ OH^{-}]= 10^{-pOH}](/tpl/images/1058/8779/250fb.png)
![[ OH^{-}] = 10^{-6.48}](/tpl/images/1058/8779/3a2a7.png)
![[ OH^{-}]=3.31* 10^{-7} M](/tpl/images/1058/8779/bbba5.png)
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What is the (oh-) in a solution with a poh of 6.48...
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