Given 7.90 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100% yield?

Answer : 9.293 g

Explanation : The reaction is 



Here, if we assume the stoichiometric esterification ratio as 1:1 then,

no. of moles of  = 7.05 g/ 88 = 8.011  moles

so here, no. of moles of ethyl butyl rate = no. of moles of butyric acid ;



= (7.05 /88.11) X 116.16 = 9.29 g