What is the concentration of no3- ions in a solution prepared by dissolving 15.0 g of ca(no3)2 in enough water to produce 300. ml of solution?

The concentration of NO₃¯ in the solution is 0.61 M

We'll begin by calculating the number of mole in 15 g of Ca(NO₃)₂. This can be obtained as follow:

Mass of Ca(NO₃)₂ = 15 g

Molar mass of Ca(NO₃)₂ = 40 + 2[14 + (16×3)]

= 40 + 2[14 + 48]

= 40 + 2[62]

= 40 + 124

= 164 g/mol

Mole = mass / molar mass

Mole of Ca(NO₃)₂ = 15 / 164

Next, we shall determine the molarity of Ca(NO₃)₂. This can be obtained as follow:

Mole of Ca(NO₃)₂ = 0.0915 mole  

Volume = 300 mL = 300 / 1000 = 0.3 L

Molarity = mole / Volume

Molarity of Ca(NO₃)₂ = 0.0915 / 0.3

Finally, we shall determine the concentration of NO₃¯ in the 0.305 M Ca(NO₃)₂ solution. This can be obtained as follow:

From the balanced equation above,

1 mole of Ca(NO₃)₂ produced 2 moles of NO₃¯.

Therefore,

0.305 M Ca(NO₃)₂  will produce = 2 × 0.305 = 0.61 M NO₃¯

Thus, the concentration of NO₃¯ in the solution is 0.61 M

Learn more: link

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.

they are all solids.