The reaction h2so4 + 2 naoh -> na2so4 + 2h2o represents an acid-base tritration. the equivalence point occurs when 24.75 ml of 0.2432 m naoh is added to a 38.94 ml portion of h2so4. what is the molar concentration of h2so4 expressed in m?

            moles NaOH = c · V = 0.2432 mmol/mL · 24.75 mL = 6.0192 mmol
            moles H2SO4 = 6.0192 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.0096 mmol
Hence
            [H2SO4]= n/V = 3.0096 mmol / 38.94 mL = 0.07729 M
The answer to this question is  [H2SO4] = 0.07729 M